Optimal. Leaf size=97 \[ \frac{(b d-a e)^{10} \left (a^2+2 a b x+b^2 x^2\right )^p (d+e x)^{m+1} \left (-\frac{e (a+b x)}{b d-a e}\right )^{-2 p} \, _2F_1\left (m+1,-2 (p+5);m+2;\frac{b (d+e x)}{b d-a e}\right )}{e^{11} (m+1)} \]
[Out]
_______________________________________________________________________________________
Rubi [A] time = 0.167613, antiderivative size = 97, normalized size of antiderivative = 1., number of steps used = 3, number of rules used = 3, integrand size = 28, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.107 \[ \frac{(b d-a e)^{10} \left (a^2+2 a b x+b^2 x^2\right )^p (d+e x)^{m+1} \left (-\frac{e (a+b x)}{b d-a e}\right )^{-2 p} \, _2F_1\left (m+1,-2 (p+5);m+2;\frac{b (d+e x)}{b d-a e}\right )}{e^{11} (m+1)} \]
Antiderivative was successfully verified.
[In] Int[(d + e*x)^m*(a^2 + 2*a*b*x + b^2*x^2)^(5 + p),x]
[Out]
_______________________________________________________________________________________
Rubi in Sympy [A] time = 41.7466, size = 83, normalized size = 0.86 \[ \frac{\left (\frac{e \left (a + b x\right )}{a e - b d}\right )^{- 2 p} \left (d + e x\right )^{m + 1} \left (a e - b d\right )^{10} \left (a^{2} + 2 a b x + b^{2} x^{2}\right )^{p}{{}_{2}F_{1}\left (\begin{matrix} - 2 p - 10, m + 1 \\ m + 2 \end{matrix}\middle |{\frac{b \left (- d - e x\right )}{a e - b d}} \right )}}{e^{11} \left (m + 1\right )} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] rubi_integrate((e*x+d)**m*(b**2*x**2+2*a*b*x+a**2)**(5+p),x)
[Out]
_______________________________________________________________________________________
Mathematica [A] time = 0.207153, size = 87, normalized size = 0.9 \[ \frac{(b d-a e)^{10} \left ((a+b x)^2\right )^p (d+e x)^{m+1} \left (\frac{e (a+b x)}{a e-b d}\right )^{-2 p} \, _2F_1\left (m+1,-2 (p+5);m+2;\frac{b (d+e x)}{b d-a e}\right )}{e^{11} (m+1)} \]
Antiderivative was successfully verified.
[In] Integrate[(d + e*x)^m*(a^2 + 2*a*b*x + b^2*x^2)^(5 + p),x]
[Out]
_______________________________________________________________________________________
Maple [F] time = 0.225, size = 0, normalized size = 0. \[ \int \left ( ex+d \right ) ^{m} \left ({b}^{2}{x}^{2}+2\,abx+{a}^{2} \right ) ^{5+p}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
[In] int((e*x+d)^m*(b^2*x^2+2*a*b*x+a^2)^(5+p),x)
[Out]
_______________________________________________________________________________________
Maxima [F] time = 0., size = 0, normalized size = 0. \[ \int{\left (b^{2} x^{2} + 2 \, a b x + a^{2}\right )}^{p + 5}{\left (e x + d\right )}^{m}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((b^2*x^2 + 2*a*b*x + a^2)^(p + 5)*(e*x + d)^m,x, algorithm="maxima")
[Out]
_______________________________________________________________________________________
Fricas [F] time = 0., size = 0, normalized size = 0. \[{\rm integral}\left ({\left (b^{2} x^{2} + 2 \, a b x + a^{2}\right )}^{p + 5}{\left (e x + d\right )}^{m}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((b^2*x^2 + 2*a*b*x + a^2)^(p + 5)*(e*x + d)^m,x, algorithm="fricas")
[Out]
_______________________________________________________________________________________
Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \[ \text{Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((e*x+d)**m*(b**2*x**2+2*a*b*x+a**2)**(5+p),x)
[Out]
_______________________________________________________________________________________
GIAC/XCAS [F] time = 0., size = 0, normalized size = 0. \[ \int{\left (b^{2} x^{2} + 2 \, a b x + a^{2}\right )}^{p + 5}{\left (e x + d\right )}^{m}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((b^2*x^2 + 2*a*b*x + a^2)^(p + 5)*(e*x + d)^m,x, algorithm="giac")
[Out]